terminal-util: return first error, not last in make_stdio()

Just a minor tweak, making sure we execute as much as we can of the
funciton, but return the first error instead of the last we encounter.

This is usuelly how we do things when we have functions that continue on
the first error, so let's do it like that here too.
This commit is contained in:
Lennart Poettering
2017-12-22 13:05:33 +01:00
parent e43bc9f526
commit 395195bb42

View File

@@ -875,25 +875,24 @@ bool on_tty(void) {
}
int make_stdio(int fd) {
int r, s, t;
int r = 0;
assert(fd >= 0);
r = dup2(fd, STDIN_FILENO);
s = dup2(fd, STDOUT_FILENO);
t = dup2(fd, STDERR_FILENO);
if (dup2(fd, STDIN_FILENO) < 0 && r >= 0)
r = -errno;
if (dup2(fd, STDOUT_FILENO) < 0 && r >= 0)
r = -errno;
if (dup2(fd, STDERR_FILENO) < 0 && r >= 0)
r = -errno;
if (fd >= 3)
safe_close(fd);
if (r < 0 || s < 0 || t < 0)
return -errno;
/* Explicitly unset O_CLOEXEC, since if fd was < 3, then
* dup2() was a NOP and the bit hence possibly set. */
/* Explicitly unset O_CLOEXEC, since if fd was < 3, then dup2() was a NOP and the bit hence possibly set. */
stdio_unset_cloexec();
return 0;
return r;
}
int make_null_stdio(void) {